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2 years ago

Is this right ? if not please help me !

Mathematics

2 answers:

sergejj [24]2 years ago

8 0

Answer:

You are correct!!! :)

Step-by-step explanation:

posledela2 years ago

7 0

Answer:

y = -3/2 x - 2

Step-by-step explanation:

This should be correct if not I'm sorry I tried my best.

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Which equation when graph has x intercepts at (2,0) and (4,0) and a y-intercept of (0,-16)?

julsineya [31]

The correct answer is C. if you plug zero in for 'x' you will get the y-intercept.
-2(0-2)(0-4)= -2(-2)(-4)=-16
Next set each factor equal to zero to get the x-intercepts.
(x-2)=0 x = 2 (2,0)
(x-4) = 0 x = 4 (4,0)

I hope this helps

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3 years ago

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Find the product of -4x 3 y 2(7xy 4)

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Answer:

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Step-by-step explanation:

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2 years ago

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What is the slope of the line shown below.

rusak2 [61]

slope = (y2-y1)/(x2-x1)

(2,4) (4,8)

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2 years ago

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Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

Answer Check

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$