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3 years ago

Answer this I don't know what is can be

Mathematics

2 answers:

slavikrds [6]3 years ago

7 0

The greatest ommon factor is 10

notka56 [123]3 years ago

5 0

The answer would be 10.
The GCF can be no larger than the smallest number.
Hope this helps. :D

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What is 4.738rounded to the nearest thousandth? (Points : 1) 4.73 4.74 4.738 4.739

Ugo [173]

The answer is 4.74 because 9 is the thousands place and the one in front of it the hundredths goes up 5 and up or 4 and below hope this helps

7 0

3 years ago

Does 24, 7, and 26 form a right triangle

const2013 [10]

Answer:

No. It is an obtuse triangle.

Step-by-step explanation:

If c^2>a^2+b^2, then the triangle is obtuse. Since 24^2 + 7^2 is 625, and the square root of 625 is 25, that means 26>25. This proves that the triangle is obtuse.

4 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

4 years ago

Find three consecutive odd integers with a sum of 63

grin007 [14]

Answer:

19, 21, and 23.

Step-by-step explanation:

4 0

3 years ago

Hey, I'm going to be using all my points on this one but can someone help me solve these? I'm having a rough time. It'd be great

Jlenok [28]

Answer:

could you just put a question i cant see them

Step-by-step explanation:

6 0

3 years ago