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Fed [463]
4 years ago
9

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

which they are chosen is not important.
Mathematics
1 answer:
algol [13]4 years ago
8 0

5 People can be chosen  in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

nCr=\frac{(n)!}{(n-r)!(r)!}

So here , n =13  and r=5 ,  

So after putting the value  of n and r , the equation will be

13C_5=\frac{(13)!}{(13-5)!(5)!}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}

13C_5=\frac{154440}{120}

13C_5= 1287

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