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bekas [8.4K]
3 years ago
5

A student solved this problem by working backward. Jared has some flowers. He has 6 more red flowers than yellow flowers. He has

twice as many orange flowers as red flowers. He has 4 yellow flowers. How many flowers does Jared have altogether? Student's solution: Jared has 4 yellow flowers. He has 6 more red than yellow flowers (4 + 6 = 10). He has twice as many orange flowers as red flowers (10 × 2 = 20). So Jared has 4 + 10 + 20 = 34 flowers. Use a similar strategy to solve this problem. Kathleen has some balloons. She has 7 more silver balloons than gold balloons. She has 3 times as many bronze balloons as silver balloons. She has 5 gold balloons. How many balloons does Kathleen have altogether?
Mathematics
1 answer:
goldenfox [79]3 years ago
4 0
5 + 7 = 12 silver balloons
12 x 3 = 36 bronze
12 + 36 + 5 = 53
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5% of 3200 is 160......
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Suppose the system of linear equations has infinitely many solutions. What is the value of y for the second equation?
Otrada [13]
I believe it would be 4

This is because when divided by 3, 3x+12y=3 turns into x+4y=3
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3 years ago
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What is 3/4 ÷ 1/6? Please help !......
Reika [66]

Answer:

4 1/2

Step-by-step explanation:

Apply the fractions formula for division, to

3/4÷1/6

and solve

3/6x4/1

=18/4

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(18,4) = 2

18/24÷2/2=9/2

Convert to a mixed number using

long division for 9 ÷ 2 = 4R1, so

9/2=4 1/2

Therefore:

3/4÷1/6=4 1/2

4 0
3 years ago
I will give brainliest to correct answer
FromTheMoon [43]

Answer:

D

Step-by-step explanation:

If the polynomial p(x) is divided by a polynomial of the form x+k (which accounts for all of the possible answer choices in this question), the result can be written as

p(x)/x+k = q(x) + r/x+k

where q(x) is a polynomial and r is the remainder. Since x+k is a degree-1 polynomial (meaning it only includes x^{1} and no higher exponents), the remainder is a real number.

Therefore, p(x) can be rewritten as p(x) = (x+k)q(x) + r, where r is a real number.

The question states that p(3) = −2, so it must be true that

−2 = p(3) = (3+k)q(3) + r

Now we can plug in all the possible answers. If the answer is A, B, or C, r will be 0, while if the answer is D, r will be −2.

A. −2=p(3)=(3+(−5))q(3)+0

−2=(3−5)q(3)

−2=(−2)q(3)

This could be true, but only if q(3)=1

B. −2=p(3)=(3+(−2))q(3)+0

−2=(3−2)q(3)

−2=(−1)q(3)

This could be true, but only if q(3)=2

C. −2=p(3)=(3+2)q(3)+0

−2=(5)q(3)

This could be true, but only if q(3) = −2/5

D. −2=p(3)=(3+(−3))q(3)+(−2)

−2=(3−3)q(3)+(−2)

−2=(0)q(3)+(−2)

This will always be true no matter what q(3) is.

Of the answer choices, the only one that must be true about p(x) is D, that the remainder when p(x) is divided by x−3 is -2.

The final answer is D.

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Answer:

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15=0

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