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Ivahew [28]
2 years ago
11

Mr. Wells tells his class of 24 that when they have completed the assignment, they may play online math games. At the end of cla

ss, 40% of the class is playing online math games. Approximately how many students still need to complete their assignment?
Mathematics
1 answer:
Doss [256]2 years ago
4 0

Answer:

14

Step-by-step explanation:

60% of 24 need to complete their tasks

this is 6x2.4=12+1.6=13.6 =14

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2 r squared + 3s cubed minus r squared + 40 squared minus r squared if R equals -2 s equals -3 and T equals 5
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2/8 or 1/4. 1/4 is just simplified. I hope it helps!
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3 years ago
Angle G is a circumscribed angle of circle E. Major arc FD measures 280°.
mixer [17]

Answer:

The answer is 40°

Step-by-step explanation:

Solution

Now,

The Measure of major arc FD = 280°

Thus,

One complete angle measure 360°

Then

m∠FED = 360 - 180

m∠FED = 80°

Thus,

FE = DE ( the same circle Radius)

∠EFD = ∠EDF (  opposite angles to equal sides are equal)

Now

Applying angle sum property of a triangle in ΔEFD

∠EFD + ∠EDF + ∠FED = 180°

∠EFD + ∠EFD + 80 = 180

2∠EFD = 100

∠EFD = 50°

Hence, GF is tangent to the circle and the tangent always make right angles with the radius of the circle.

∠EFG = 90°

∠GFD + ∠EFD = 90°

∠GFD + 50 = 90

∠GFD = 40°

Therefore, The measure of the angle GFD is 40°

8 0
3 years ago
Read 2 more answers
Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th
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I'm guessing the function is

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which, split into partial fractions, is equivalent to

\dfrac1{x-6}-\dfrac1{x+2}

Recall that for |x| we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

With some rearranging, we find

\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n

valid for \left|\dfrac x6\right|, or |x|, and

\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n

valid for \left|-\dfrac x2\right|, or |x|.

So we have

f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n

f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)

f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n

Taken together, the power series for f(x) can only converge for |x|, or -2.

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3 years ago
The table below shows the probability distribution of students in a high school with 1500 students. What is the expected value f
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4 0
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