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Korvikt [17]
3 years ago
12

Suppose the system of linear equations has infinitely many solutions. What is the value of y for the second equation?

Mathematics
2 answers:
Otrada [13]3 years ago
6 0
I believe it would be 4

This is because when divided by 3, 3x+12y=3 turns into x+4y=3
algol [13]3 years ago
5 0

Answer:

D. 4

Step-by-step explanation:

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4 people went to the movies. Each person spent $9.50 on a ticket and had the same amount of money leftover. They originally had
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$2.50 was left for each person.

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subtract 38 on both sides

x = 10

10$ was left in total by all 4 people

10/4 = 2.50

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3 years ago
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If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
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Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
What do you notice about the table inputs for the graph of √x?
Airida [17]

Answer:

See below

Step-by-step explanation:

When we talk about the function f(x)=\sqrt{x}, the domain and codomain are generally defaulted to be subsets of the Real set. Once $f:[0,\infty)\to [0,\infty)$ and  $f\subseteq [0,\infty)\times [0,\infty)$ such that $(x,y_1)\in f\wedge(x,y_2)\in f \Rightarrow y_1=y_2$  for $f(x)=\sqrt x$. Therefore,

\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]

\[x \mapsto \sqrt{x}\]

But this table just shows the perfect square solutions.

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2 years ago
Please help to find the HCF and LCM of this question ​
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Step-by-step explanation:

Explanation is in the attachment

<em>H</em><em>ope </em><em>it</em><em> is</em><em> helpful</em><em> to</em><em> you</em>

<em> </em><em> </em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em>

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