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Korvikt [17]
4 years ago
12

Suppose the system of linear equations has infinitely many solutions. What is the value of y for the second equation?

Mathematics
2 answers:
Otrada [13]4 years ago
6 0
I believe it would be 4

This is because when divided by 3, 3x+12y=3 turns into x+4y=3
algol [13]4 years ago
5 0

Answer:

D. 4

Step-by-step explanation:

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I need the solutions
MAXImum [283]

Answer:

(-1, -2)

Step-by-step explanation:

The solution is the intersection, which is at (-1, -2)

4 0
3 years ago
If f is the function defined by f(x) = 3x^5 - 5x^4, what are all the x coordinates of points of inflection for the graph of f?
gregori [183]

Answer:

D: 0 and 1

Step-by-step explanation:

Function is defined by;

f(x) = 3x^(5) - 5x⁴

Now, an inflection point will be a point on the graph where the inflection or concavity changes.

Thus, let's find the derivatives until we get there;

f'(x) = 15x⁴ - 20x³

f''(x) = 60x³ - 60x²

So factorizing gives;

f''(x) = 60x²(x - 1)

At f''(x) = 0, we have; x = 0 or x = 1

Thus, the x coordinates of points of inflection are 0 & 1

4 0
3 years ago
Tell whether 12/8 and 3/6 form a proportion
Rus_ich [418]

Answer:

yes they do.... multiply 3/6 by 3 = 12/8

12/8 multiply by 1/3 = 3/6 or 1/2

Step-by-step explanation:

Don't you dare delete again eupora you are dum

my answer was correct you evil

6 0
3 years ago
A student performed the following system to find the solution to the equation x2-2x-8=0
Molodets [167]

The student messed up on step one. The proper factoring is (x-4) (x+2)

5 0
4 years ago
Read 2 more answers
Solve for g.<br> -3+5+6g=11-3g−3+5+6g=11−3g
PtichkaEL [24]

Answer: \mathrm{No\:Solution}

Step-by-step explanation:

\begin{bmatrix}-3+5+6g=1\\ 1-3g+5+6g=11-3g\end{bmatrix}

\begin{bmatrix}1-3\left(-\frac{1}{6}\right)+5+6\left(-\frac{1}{6}\right)=11-3\left(-\frac{1}{6}\right)\end{bmatrix}

\begin{bmatrix}\frac{11}{2}=\frac{23}{2}\end{bmatrix}

\frac{11}{2}=\frac{23}{2}\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}

4 0
3 years ago
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