X = 5 so that would mean if you plug it into both equations, segment CD would be 32 units long.
Here's an example. We'll test the last set of data: 10, 15, 16, 16, 18, 19, 21, 25. The median is the average of the 2 middle data points: (16+18)/2 = 17. So far, so good, since the diagram shows a median of 17.
First Quartile: find the median of 10, 15, 16, 16; it is the average of 15 and 16, which comes to 15.5. Third quartile: find the median of 18, 19, 21, 25. It's 20. Does the graph show this? No. The First Quartile in the graph is 15, not 15.5 (but this is not very far off). The Third Quartile in the graph is 20, which matches. So, the fourth set of data might be an answer.
You must check out the other 3 data sets in the same manner. Pick the set that is most closely illustrated by the diagram.
Answer:
i believe the answer is 46. good luck!
Answer:
1) n=$35-$19
2) n=$16
Step-by-step explanation:
Answer: Hello!
first let's note the things we already know:
there is a 16- lap race and the oval has one mile of length, then each of the laps has a length of one mile, and the whole race has 16 miles in total
Bobby averages 94 mph and already did 6 laps ( or 6 miles)
then we could write the Bobby equation as B(t) = 6 miles + 94mph*t
where t represents the time in hours.
now we could see how much time Bobby needs to end the race:
B(x) = 6mi + 94mph*x = 16mi
94mph*x = 16mi - 6mi = 10mi
x = (10/94)h = 0.106h
so Bobby needs 0.106 hours to finish the race, and we want to know which velocity Rick should have in order to reach the end of the race at the same time as Bobby.
Rick is starting the race, so he needs to do 16 miles in 0.106 hours, and as we know velocity is distance over time; so the average velocity of Rick is:
V = 16mi/0.106h = 150.9mph
Now let's see the hint:
Bobby does 8 miles in:
94*t = 8
t = 8/94 = 0.085 hours
and Rick does 10 miles in:
150.9*t = 10
t = 10/150.9 = 0.066 hours
wich is clearly different times, so maybe the hint is wrong.