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4 years ago

11

Help me help me help me help me

2 answers:

MatroZZZ [7]4 years ago

5 0

Here's an example. We'll test the last set of data: 10, 15, 16, 16, 18, 19, 21, 25. The median is the average of the 2 middle data points: (16+18)/2 = 17. So far, so good, since the diagram shows a median of 17.
First Quartile: find the median of 10, 15, 16, 16; it is the average of 15 and 16, which comes to 15.5. Third quartile: find the median of 18, 19, 21, 25. It's 20. Does the graph show this? No. The First Quartile in the graph is 15, not 15.5 (but this is not very far off). The Third Quartile in the graph is 20, which matches. So, the fourth set of data might be an answer.

You must check out the other 3 data sets in the same manner. Pick the set that is most closely illustrated by the diagram.

Leto [7]4 years ago

3 0

Answer:

option 3

Step-by-step explanation:

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Help out please thank you

Helga [31]

Answer:

x = 26

Step-by-step explanation:

The three angles form a straight line, so they will sum to 180

4x - 8 + 34 + 76- x = 180

Combine like terms

3x+ 102 = 180

Subtract 102 from each side

3x+102-102 = 180-102

3x= 78

Divide each side by 3

3x/3 = 78/3

x = 26

3 0

3 years ago

Solve the inequality and graph the solution |7x-7|+2<23

Naya [18.7K]

$|7x-7|+2 < 23\ \ \ \ \ |-2\\\\|7x-7| < 21\iff7x-7 < 21\ \wedge\ 7x+7 > -21\ \ \ \ \ \ |+7\\\\7x < 28\ \wedge\ 7x > -14\ \ \ \ \ \ \ |:7\\\\x < 4\ \wedge\ x > -2\\\\-2 < x < 4$

3 0

3 years ago

If m∠2=39 and m∠3=30, what is m∠1?

satela [25.4K]

Answer:

The answer would be A.) 111

Step-by-step explanation:

The angles of any triangle must add up to 180. So you subtract ∠1 and ∠2 from 180 and you will get the 3rd angle.

7 0

3 years ago

The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

8 0

3 years ago

Help please with this math ;-; I beg of you

RSB [31]

Answer:

49 - 9π

Step-by-step explanation:

Area of white portion = area of triangle - area of circle

To find the area of the triangle:

The area of a triangle can be calculated using this formula

$A=\frac{bh}{2}$ where b = base length and h = height

The height given is 7m and the base length given is 14m

That being said we plug in the given values into the formula

$\frac{14*7}{2} \\14*7=98\\\frac{98}{2} =49$

Hence, the area of the triangle is 49 sq meters.

To find the area of circle

( note that the area is in terms of pi; shown by the answer choices. )

Formula for area of a circle = $A=\pi r^2$

We are given the diameter ( 6m )

However, we need the radius

To convert diameter to radius we divide by 2

6/2 = 3 so the radius = 3m

Now we plug in 3 into the formula

$A=\pi 3^2\\3^2=9\\A=9\pi$

Remember we do not apply pi because the answer should be in terms of pi.

Now we subtract the two

Area of white portion = 49 - 9π

Hence, the answer is A

7 0

3 years ago

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