well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
93+(68+7)do whats in the parenthesis first
93(75)
multiply them together
6975 is your answer plz rate my answer as brainliest
Answer:
Step-by-step explanation:
The population in 2003= 47000
Since the population increase by 1200 every year,
in 2004 the population will be 47000+1200
in 2005 the population will be 47000+(1200+1200) which is the same as
47000+2(1200) where 2 is 2 years after 2003,
Therefore the population x years after 2003 is 47000+x(1200).
P= 47000+1200x
b) The population at 2009 which is 6 years after 2003 will be
47000+(1200)*6=47000+7200= 54200
The population at 2009 is 54200,