Answer:
Dryer cost $475; Washer cost $382
Step-by-step explanation:
For this problem, we will simply set up a system of equations to find the value of each the washer (variable x) and the dryer (variable y).
We are given the washer and dryer cost $857 together.
x + y = 857
We are also given that the washer cost $93 less than the dryer.
x = y - 93
So to find the cost of the dryer, we simply need to find the value of y.
x + y = 857
x = y - 93
( y - 93 ) + y = 857
2y - 93 = 857
2y = 950
y = 475
So now we have the value of the dry to be $475. We can check this by simply plugging in the value and see if it makes sense.
x + y = 857
x + 475 = 857
x = 382
And check this value:
x = y - 93
382 ?= 475 - 93
382 == 382
Therefore, we have found the values of both the washer and the dryer.
Cheers.
Answer:
$13,640
Step-by-step explanation:
money that need to pay for the tuition for all four years
=$16,110×4
=$64,440
the money he had
=$45,800+$5,000
=$50,800
the difference
=$64,440-$50,800
=$13,640
Answer:
<u>So option 4; </u>
<u> is the correct option</u>
Step-by-step explanation:
First, we need to convert
so it's denominator is 100. To do so, we will multiply the numerator and denominator by 10

Second, we need to add the two fractions to get the current total distance walked. Remember, when adding fractions, the denominator does not change.

Now that we have the total distance walked, we need to subtract that to 1 mile. 

So option 4;
is the correct option
A regular trapezoid is shown in the picture attached.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:

A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is
12√6 square units.