All categories

3 years ago

Plz awnser i have ixl and ive already crack my screen so help no explanation just awnsrr

Mathematics

1 answer:

rjkz [21]3 years ago

3 0

The answer is 6c=2.75 hope this helps

You might be interested in

in which place is the digit in the numbers 5,341 that would be changed to form 5,841? how do the values of the two numbers compa

Akimi4 [234]

The changed digit is the third to the left of the decimal point, so is in the hundreds place.

The value of 8 hundred is 5 hundred more than the value of 3 hundred. The second number is 500 more than the first.

7 0

2 years ago

Use a system of linear equations with two variables and two equations to solve. A number is 9 more than another number. Twice

Troyanec [42]

9514 1404 393

Answer:

(x, y) = (3, 12)

Step-by-step explanation:

Using the given variable definitions, we can write the equations ...

y = x + 9

2(x +y) = 30

Solving the second equation for y, we have ...

y = 15 -x

Substituting this into the first equation gives ...

15 -x = x +9

6 = 2x . . . . . . . . . add x-9

3 = x . . . . . . . . . . divide by 2

y = 3+9 = 12 . . . . substitute into the first equation

The numbers are (x, y) = (3, 12).

4 0

2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Find the percent of change when the price of a radio changes from $40.00 to $44.00.

HACTEHA [7]

1) 10%
2)12%
3)20%
4)8%
5)50%

7 0

2 years ago

Please answer this correctly

Lynna [10]

Answer:

75%

Step-by-step explanation:

There is 1 whisker and quartiles 1-3 so:

25%+25%+25%=75%

6 0

2 years ago