Answer:
a x a x a x a x a x a
Step-by-step explanation:
a^4 x a^2
a x a x a x a times a x a
= a^6 or a x a x a x a x a x a
<h2>
Hello!</h2>
The answers are:
a) The name of function is f.
b) Independent variable : x , dependent variable : y/f(x)
c) The rule that assings exactly one output to the very input is called "function".
d) ![f(4)=\frac{3}{4+2}=\frac{3}{7}](https://tex.z-dn.net/?f=f%284%29%3D%5Cfrac%7B3%7D%7B4%2B2%7D%3D%5Cfrac%7B3%7D%7B7%7D)
<h2>Why?</h2>
Usually, the name of a function
is what is out of the parentheses, so the name of the function is "f".
The independent variable of a function is the variable we assign the different values, so, for this case, the independent variable is designated with the letter "x"
The dependent variable is the function itself, it's also called "y", it's called "dependent" variable because its values will always depend on the "independent variable"
A function is a rule that states that there is exactly one output (range value) to the very input (domain value). A function only exists when there is exactly one output value (range) for each input (domain), if there is more than one output for each input, the function does not exist.
Evaluating a function consists of assign values to the independent variable(x), hence:
![f(4)=\frac{3}{4+2}=\frac{3}{7}](https://tex.z-dn.net/?f=f%284%29%3D%5Cfrac%7B3%7D%7B4%2B2%7D%3D%5Cfrac%7B3%7D%7B7%7D)
Have a nice day!
5/54 or approximately 0.092592593
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
r = 4, y = 2, b = 1, so n = 3 + 1 = 4
r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
r = 5, y = 3, b = {1,2}, so n = 7 + 2 = 9
r = 5, y = 2, b = 1, so n = 9 + 1 = 10
And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
r = 6, y = 2, b = 1, so n = 19 + 1 = 20
And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.
Answer:
3
+ 6x - 1
Step-by-step explanation:
(-5
+ 4x - 2) + ( 8
+ 2x + 1)
1.Remove parenthesis
-5
+ 4x - 2 + 8
+ 2x + 1
2. Combine like terms
3
+ 6x - 1
We know the first place after decimal is tenths
The second place after decimal is hundredths
The third place after decimal is the thousandths place
So for 0.056
0 is at the tenths place
5 is at the hundredths place
and 6 is at the thousandths place
Expanding 22.056 we get
22.056 = 20 + 2 + 0.05 + 0.006
OR
22.056 = ![20+2+\frac{5}{100}+\frac{6}{1000}](https://tex.z-dn.net/?f=20%2B2%2B%5Cfrac%7B5%7D%7B100%7D%2B%5Cfrac%7B6%7D%7B1000%7D)