All categories

1 year ago

Which is equivalent to sin-1(–0. 4)? Round your answer to the nearest hundredth of a radian.

1 answer:

8 0

Using the relationship between the degree and radian. Then the equivalent of $\rm sin^{-1} (-0.4)$ is 5.87 radians.

<h3>What is an equivalent function?</h3>

The equivalent is the functions that are in different forms but are equal to the same value.

Given

The expression is $\rm sin ^{-1}(-0.4)$ .

Then the angle will be

$\rm sin^{-1} (-0.4) = -23.58\\\\sin^{-1} (-0.4) = -23.58 + 360\\\\sin^{-1} (-0.4) = 336.42$

The angle 336.42 is in degrees.

Conversion of degree into radian.

$\begin{aligned}\rm 1 degree &= \dfrac{2\pi}{360}\\\\336.42\rm \ degrees &= \dfrac{\pi}{180}*336.42 \\\\336.42 \rm \ degrees &= 5.87\end{aligned}$

Thus, The equivalent of $\rm sin^{-1} (-0.4)$ is 5.87 radians.

More about the equivalent link is given below.

brainly.com/question/10498970

You might be interested in

Can somebody please help me with these

Softa [21]

The first pic is A. because 1.2 x 10=12

8 0

2 years ago

The second term in a geometric sequence is 50. The fourth term in the same sequence is 112.5 . What is the common ration in this

ale4655 [162]

Let the common ratio be r.
then
a2*r*r=a4
rearrange,
r^2=a4/a2=112.5/50=2.25
r=sqrt(2.25)=1.5 = common ratio

7 0

2 years ago

Whats the solution to x-7>-5

Scorpion4ik [409]

X-7 > -5
x < -5-7
x < -12

3 0

2 years ago

Help. Find the value of x to the nearest tenth

vodka [1.7K]

I will assume that line 4 bisect line x exactly in half. This means that if we solve the last side of the triangle like seen in the pic below we will know what half of line x is

To find the length of the last side of the triangle (let's call this y) you must use Pythagorean theorem

$a^{2} +b^{2}=c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 4

b = y

c = 6

^^^Plug these numbers/variables into the theorem

$4^{2} +y^{2} =6^{2}$

solve for y

16 + $y^{2}$ = 36

$y^{2}$ = 20

x = √20

x ≈ 4.472

^^^This is only half of x so if you double it then it will get you the full length of x

4.472 * 2 = 8.944

8.9 (D)

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

2 years ago

Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

6 0

2 years ago

Read 2 more answers