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bixtya [17]
4 years ago
7

Functions, I appear to be confused upon this particular question

Mathematics
1 answer:
frosja888 [35]4 years ago
4 0
\bf \begin{cases}
f(x)=-x-2\\
g(x)=x^2\\
(g\circ f)(-6)\implies g[~~f(-6)~~]
\end{cases}
\\\\\\
\textit{now, what is f(-6)?}\qquad f(-6)=-\stackrel{x}{(-6)}-2\implies f(-6)=6-2
\\\\\\
\boxed{f(-6)=4}
\\\\\\
g[~~f(-6)~~]\implies g[~~4~~]=(4)^2
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The surface area of a sphere is decreasing at the constant rate of 3π sq. cm/sec . At what rate is the volume of the sphere decr
olga nikolaevna [1]
Whooh



SA=4pir²
take derivitive
dSA/dt=8pir dr/dt

and do the volume as well
V=(4/3)pir³
dV/dt=4pir² dr/dt

we need to solve for dV/dt
to do taht we need dr/dt
so

dSA/dt=8pir dr/dt
given dSA/dt=3pi cm/sec
r=2
3pi=8pi2 dr/dt
3=16 dr/dt
3/16=dr/dt

now do the volume
dV/dt=4pir² dr/dt
r=2
dr/dt=3/16
dV/dt=4pi2² (3/16)
dV/dt=16pi(3/16)
dV/dt=3pi

nice
the volume of the sphere is decreasing at 3pi cm/sec as well
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3 years ago
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Oksi-84 [34.3K]
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4 years ago
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