Answer:
a. 0.0000
b. 0.9949
c. 0.0212
d. 1.0000
Step-by-step explanation:
a. This is a binomial probability distribution problem of the form:

#Given n=15, p=0.56, the probability of none will order a non-alcoholic drink:


Hence, the probability that none will order a non-alcoholic drink is 0.0000
b. The probability that at least 4 will order a non-alcoholic drink is:

Hence, the probability of at least 4 non-alcoholic orders is 0.9949
c. The Probability that fewer than 5 orders will be made is calculated as:

Hence, the probability of less than 5 orders is 0.0212
d. The probability of all orders being non-alcoholic is equivalent to 1 minus no order being non-alcoholic.
-From a above, the probability of zero non-alcoholic order is , P(X=0)=0000045
-Therefore:


Hence, the probability that all orders are non-alcoholic 1.0000