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slega [8]
3 years ago
9

From a group of 10 people, 5 are selected at random to participate in a game show. In how many ways can the 5 people be selected

? A. 120 B. 252 C. 30,240 D. 100,000
Mathematics
2 answers:
diamong [38]3 years ago
6 0

Answer:

A) 120

Step-by-step explanation:

For this question you will need to use factorials

5! =5×4×3×2×1

which equals to 120

therefore the 5 people can be selected in 120 different ways

hope this helps

sergeinik [125]3 years ago
3 0

Answer:

The correct option is B. 252

Step-by-step explanation:

Total number of peoples in the group = 10

Number of peoples needed to be selected from the group of 10 peoples = 5

We need to find the total number of ways in which we can select the 5 peoples.

\text{So, Number of ways of selecting the 5 people out of 10 = }_5^7 \txterm{C}

\text{So, Number of ways of selecting the 5 people out of 10 = }\frac{10!}{5!\times 5!}

\text{So, Number of ways of selecting the 5 people out of 10 = }252

Hence, Total number of required ways = 252

Therefore, The correct option is B. 252

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Veronika [31]

Answer:

Correct option is (d): Neither X nor Y can be well-approximated by a normal random variable.

Step-by-step explanation:

The sample size of males having color-blindness is, n (X) = 20.

The sample size of females having color-blindness is, n (Y) = 40.

The proportion of males that suffer from color-blindness is, P (X) = 0.08.

The proportion of females that suffer from color-blindness is, P (Y) = 0.01.

Now both the random variables <em>X</em> and <em>Y</em> follows a Binomial distribution,

X\sim Bin(20, 0.08)\\Y\sim Bin(40, 0.01)

A normal distribution is used to approximate the binomial distribution if the sample is large, i.e <em>n</em> ≥ 30 and the probability of success is very close to 0.50.

Also if <em>np</em> ≥ 10 and <em>n</em> (1 - <em>p</em>) ≥ 10, the binomial distribution can be approximated by the normal distribution.

<u>For the sample of men (X):</u>

np=20\times0.08=1.610

In this case neither <em>n</em> > 30 nor <em>p</em> is close to 0.50.

And <em>np</em> < 10.

Thus, the random variable <em>X</em> cannot be approximated by the normal distribution.

<u>For the sample of men (Y):</u>

np=40\times0.01=0.410

In this case <em>n</em> > 30 but <em>p</em> is not close to 0.50.

And <em>np</em> < 10.

Thus, the random variable <em>Y</em> cannot be approximated by the normal distribution.

Thus, both the random variables cannot be approximated by the normal distribution.

The correct option is (d).

3 0
3 years ago
5 of 8
aleksandr82 [10.1K]

Given:

The mean age of 5 people in a room is 26 years.

A person enters the room. The mean age is now 33.

To find:

The age of the person who entered the room.

Solution:

Formula for mean:

\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}

The mean age of 5 people in a room is 26 years.

26=\dfrac{\text{Sum of ages of 5 people}}{5}

26\times 5=\text{Sum of ages of 5 people}

130=\text{Sum of ages of 5 people}

The mean age is now 33. It means, the mean age of 6 people is 33.

33=\dfrac{\text{Sum of ages of 6 people}}{6}

33\times 6=\text{Sum of ages of 6 people}

198=\text{Sum of ages of 6 people}

Now, the age of the person who entered the room is

Required age = Sum of ages of 6 people - Sum of ages of 5 people

                       = 198-130

                       = 68

Therefore, the age of the person who entered the room is 68 years.

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<span><span> x4-10x2+9=0</span> </span>Four solutions were found :<span> x = 3 x = -3 x = 1 x = -1</span>

Step by step solution :<span>Step  1  :</span>Skip Ad
<span>Equation at the end of step  1  :</span><span> ((x4) - (2•5x2)) + 9 = 0 </span><span>Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> x4-10x2+9</span> 

The first term is, <span> <span>x4</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> <span>-10x2</span> </span> its coefficient is <span> -10 </span>.
The last term, "the constant", is  <span> +9 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • 9 = 9</span> 

Step-2 : Find two factors of   9  whose sum equals the coefficient of the middle term, which is  <span> -10 </span>.

<span>     -9   +   -1   =   -10   That's it</span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  -1 
                     <span>x4 - 9x2</span> - <span>1x2 - 9</span>

Step-4 : Add up the first 2 terms, pulling out like factors :
                    <span>x2 • (x2-9)</span>
              Add up the last 2 terms, pulling out common factors :
                     1 • <span>(x2-9)</span>
Step-5 : Add up the four terms of step 4 :
                    <span>(x2-1)  •  (x2-9)</span>
             Which is the desired factorization

<span>Trying to factor as a Difference of Squares : </span>

<span> 2.2 </span>     Factoring: <span> x2-1</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1
Check : <span> x2  </span>is the square of  <span> x1 </span>

Factorization is :       (x + 1)  •  (x - 1) 

<span>Trying to factor as a Difference of Squares : </span>

<span> 2.3 </span>     Factoring: <span> x2 - 9</span> 

Check : 9 is the square of 3
Check : <span> x2  </span>is the square of  <span> x1 </span>

Factorization is :       (x + 3)  •  (x - 3) 

<span>Equation at the end of step  2  :</span> (x + 1) • (x - 1) • (x + 3) • (x - 3) = 0 <span>Step  3  :</span>Theory - Roots of a product :

<span> 3.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

<span>Solving a Single Variable Equation : </span>

<span> 3.2 </span>     Solve  :    x+1 = 0<span> 

 </span>Subtract  1  from both sides of the equation :<span> 
 </span>                     x = -1 

<span>Solving a Single Variable Equation : </span>

<span> 3.3 </span>     Solve  :    x-1 = 0<span> 

 </span>Add  1  to both sides of the equation :<span> 
 </span>                     x = 1 

<span>Solving a Single Variable Equation : </span>

<span> 3.4 </span>     Solve  :    x+3 = 0<span> 

 </span>Subtract  3  from both sides of the equation :<span> 
 </span>                     x = -3 

<span>Solving a Single Variable Equation : </span>

<span> 3.5 </span>     Solve  :    x-3 = 0<span> 

 </span>Add  3  to both sides of the equation :<span> 
 </span>                     x = 3 

Supplement : Solving Quadratic Equation Directly<span>Solving <span> x4-10x2+9</span>  = 0 directly </span>

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula 

<span>Solving a Single Variable Equation : </span>

Equations which are reducible to quadratic :

<span> 4.1 </span>    Solve  <span> x4-10x2+9 = 0</span>

This equation is reducible to quadratic. What this means is that using a new variable, we can rewrite this equation as a quadratic equation Using  w , such that <span> w = x2</span>  transforms the equation into :
<span> w2-10w+9 = 0</span>

Solving this new equation using the quadratic formula we get two real solutions :
   9.0000  or   1.0000

Now that we know the value(s) of <span> w</span> , we can calculate <span> x</span>  since <span> x</span> <span> is  </span><span> √<span> w </span></span> 

Doing just this we discover that the solutions of 
  <span> x4-10x2+9 = 0</span>
  are either : 
  x =√<span> 9.000 </span>= 3.00000  or :
  x =√<span> 9.000 </span>= -3.00000  or :
  x =√<span> 1.000 </span>= 1.00000  or :
  x =√<span> 1.000 </span>= -1.00000 

Four solutions were found :<span> x = 3 x = -3 x = 1 x = -1</span>

<span>
Processing ends successfully</span>

5 0
2 years ago
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