Because the cos theta < 0 then theta must be an obtuse angle
so a^2 + b^2 < a^2
C
Answer: x=9
Step-by-step explanation:
The bottom triangle that has a 40° is an isosceles triangle, therefore the other angle at the bottom right is also 40°. This leaves the top angle to be 100°.
180=40+40+x
180=80+x
x=100
Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°
180-100=∠2
80°=∠2
The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.
80=9x-1
81=9x
x=9
The coordinates of A will be (2P +M)/3
= (2(16, 14) +(1, 4))/3 = (33/3, 32/3) = (11, 32/3)
The appropriate choice is
(C) (11, 32/3)
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You will note that the coordinates of A are the weighted average of the coordinates of the end points. The weighting is the reverse of the ratio of the line segments. That is, the point adjacent to the shortest segment gets the highest weighting. (This is typical of the solution to "mixture" problems.)
Answer:
I believe the answer is C
Step-by-step explanation:
The answer to the question is x = 0
