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rusak2 [61]
3 years ago
12

Una avioneta despega con un ángulo de elevación de 12° respecto al suelo si ha recorrido 48 metros en la misma dirección ¿a que

altura respecto al suelo se encuentra la avioneta en ese momento
Mathematics
1 answer:
victus00 [196]3 years ago
7 0

Answer: 9.98 meters

Step-by-step explanation:

Angle = 12°

Displacement = 48 m

The height, or displacement in the y-axis will be equal to the opposite cathetus of a triangle rectangle where the hypotenuse is the displacement, then we can find that the displacement in the y-axis is:

h = sin(12°)*48m = 9.98m

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Answer:

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Step-by-step explanation:

<u>Use the Pythagorean Theorem</u>

The equation for the Pythagorean Theorem is \tt a^2+b^2=c^2

* a and b are the lengths of the legs, and c is the hypotenuse.*

(To know which side is the hypotenuse look at longest side which is across the right angle).

a= x, b=8, c=9

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Let's Plug in the side lengths:

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Subtract 64 from both sides:

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2 years ago
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Step-by-step explanation:

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3 years ago
E
Evgesh-ka [11]

Answer:

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Thenks and meak me brainliest :))

3 0
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