Una avioneta despega con un ángulo de elevación de 12° respecto al suelo si ha recorrido 48 metros en la misma dirección ¿a que altura respecto al suelo se encuentra la avioneta en ese momento
1 answer:
Answer: 9.98 meters
Step-by-step explanation:
Angle = 12°
Displacement = 48 m
The height, or displacement in the y-axis will be equal to the opposite cathetus of a triangle rectangle where the hypotenuse is the displacement, then we can find that the displacement in the y-axis is:
h = sin(12°)*48m = 9.98m
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