Check solution x-5/-2=x-1/-3

harina [27]

Answer is OD. Equals 10

3 0

3 years ago

Priscilla bought cheese that weighs ¾ of a pound. If she divides it into portions that are each 1/8 of a pound, how many portion

lakkis [162]

Answer:

6

Step-by-step explanation:

Priscilla bought cheese that weighs ¾ of a pound. If she divides it into portions that are each 1/8 of a pound, how many portions can she make?

¾÷⅛= 6

answer 6

4 0

3 years ago

the perimeter of a triangle is 12b+5. Two sides have the following length:4b and 3b+15. What is the length of the third side?

scZoUnD [109]

Answer:The length of the third side 2.5.

Step-by-step explanation:

We already know the length of two side but we don’t know the length of one side so we will represent it by b and we know they three lengths add up to 12b+5.

4b + 3b+15 +b =12b + 5

Solve for b.

8b +15=12b +5

-8b -8b

15+4b +5

-5 -5

4b/4=10/4

B=2.5

So the length of the third side is 2.5

4(2.5) + 3(2.5)+15+2.5=12(2.5)+5

35=35

5 0

3 years ago

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

3 years ago

You have 1 blue suit, 2 black suits, and 1 brown suit, You also have 2 blue ties, 3 red ties, and 3 pink ties. What is the proba

tia_tia [17]

The probability that you pick a striped shirt AND a blue suit is 1/4 AND a pink tie is 3/8.

According to the statement

Number of blue suit = 1

Number of black suit = 2

Number of brown suit = 1

Number of blue ties = 2

Number of red ties = 3

Number of pink ties = 3

Now we find the probability by its formula

Probability that picked suit is blue = blue suits/ total number of suits

Probability = 1/4

Now,

Probability that picked tie is pink = Pink tie / total number of ties

Probability = 3/8

So, The probability that you pick a striped shirt AND a blue suit is 1/4 AND a pink tie is 3/8.

Learn more about PROBABILITY here brainly.com/question/7965468

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8 0

2 years ago