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2 answers:
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There are 120 ways in which 5 riders and 5 horses can be arranged.
We have,
5 riders and 5 horses,
Now,
We know that,
Now,
Using the arrangement formula of Permutation,
i.e.
The total number of ways ,
So,
For n = 5,
And,
r = 5
As we have,
n = r,
So,
Now,
Using the above-mentioned formula of arrangement,
i.e.
The total number of ways ,
Now,
Substituting values,
We get,
We get,
The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,
So,
There are 120 ways to arrange horses for riders.
Hence we can say that there are 120 ways in which 5 riders and 5 horses can be arranged.
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Answer:
The scale factor is (√10) / (4)
Explanation:
The complete question as well as the rule for the distance between two points are shown in the attached image.
To get the scale factor, we will follow these steps:
1- Length of AB:
AB = √(5-9)²+(-4-4)²
AB = √80
AB = 4√5 units
2- Length of A'B':
A'B' = √(5-6)²+(-4-3)²
A'B' = √50
A'B' = 5√2
3- getting the scale factor:
A'B' = k AB where k is the scale factor
5√2 = k * 4√5
k = (√10) / (4)
Hope this helps :)
The scale factor is (√10) / (4)
Explanation:
The complete question as well as the rule for the distance between two points are shown in the attached image.
To get the scale factor, we will follow these steps:
1- Length of AB:
AB = √(5-9)²+(-4-4)²
AB = √80
AB = 4√5 units
2- Length of A'B':
A'B' = √(5-6)²+(-4-3)²
A'B' = √50
A'B' = 5√2
3- getting the scale factor:
A'B' = k AB where k is the scale factor
5√2 = k * 4√5
k = (√10) / (4)
Hope this helps :)