Here, trapezoid is composed of two triangles, and one rectangle.
So, Area of rectangle = 4 * 7 = 28 cm²
Area of a triangle = 1/2 * 3 * 7 = 21/2 = 10.5 cm²
Area of Trapezoid = area of rectangle + 2(area of triangle)
= 28 + 2(10.5)
= 28 + 21 = 49
In short, Your Answer would be 49 cm²
Hope this helps!
Jack is 10 blocks away from the school
m∠AOC = 108°
m∠AOC = 3m∠AOB
⇒m∠AOB = (m∠AOC) / 3 = 108 / 3 = 36°
f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.
, written in vertex form is
, where (h, k) = (-1, -11)
Therefore, range ={y|y ≥ -11}
Answer:
1. x = 21
2. x = 19
Step-by-step explanation:
Since the interior angles of all quadrilaterals add up to 360, all we have to do is add them up and set them equal to 360. Combine like terms and we get
7x + 213 = 360
Which further turns to 7x = 147
So x = 21
For the second problem, it's the same thing
By the end we get 2x + 8 = 46
2x = 38
x = 19
Hope this helps
