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kykrilka [37]
4 years ago
8

The 20-ml volume of water added to the erlenmeyer flask is to be previously boiled, deionized water. since water does absorb co2

from the atmosphere and since co2 dissolved in water causes it to be slightly acidic, will the use of deionized water that has not been previously boiled cause the mass of acetic acid in the vinegar to be calculated as too high or too low? explain.
Chemistry
1 answer:
Alecsey [184]4 years ago
4 0

The amount of acetic acid in vinegar is determined by the volumetric titration of acetic acid with standardized NaOH solution. When atmospheric carbon dioxide is absorbed by deionized water used in the titration, it would react with water and form carbonic acid.

CO_{2}(aq) + H_{2}O(l)  H_{2}CO_{3}(aq)

When the deionized water is contaminated with carbonic acid, it would result in the consumption of a higher amount of NaOH for neutralization. Therefore, the amount of acetic acid determined would be too <u>high</u> than it should be.

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Answer:

Energy is stored in the covalent bonds :)

Explanation:

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In a colligative properties experiment, a lab group prepares four solutions and one pure solvent sample. What is the purpose of
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3 years ago
If 1.00 g of reactant a is mixed with 2.00 g of reactant b, what is the theoretical yield of product d, in grams (g)? the molar
WARRIOR [948]

The chemical reaction is as follows:

a+b\rightarrow d

Mass of reactant a is 1 g and molar mass is 94 g/mol. Converting mass into number of moles as follows:

n=\frac{m}{M}=\frac{1g}{94 g/mol}=0.0106 mol

Now, 1 mole of reactant a gives 1 mole of product d thus, 0.0106 mol of reactant a gives 0.0106 mol of product d.

Molar mass of product d is 125 g/mol, converting number of moles into mass as follows:

m=n×M=0.0106 mol×125 g/mol=1.33 g

Similarly, molar mass of reactant b is 118 g/mol and mass is 2 g, converting mass into number of moles,

n=\frac{m}{M}=\frac{2g}{118 g/mol}=0.017 mol

1 mol of reactant b gives 1 mol of product d thus, 0.017 mol will give 0.017 mol of product d.

Converting number of moles into mass as follows:

m=n×M=0.017 mol×125 g/mol=2.12 g

Here, reactant that produces lesser product is limiting reactant and the amount of product it forms is theoretical yield.

Therefore, theoretical yield is 1.33 g.


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