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stira [4]
3 years ago
5

The Main Purpose of the US passing the Neutrality Act in 1939 on a crash and carry basis was to

Chemistry
1 answer:
Nina [5.8K]3 years ago
4 0
Hope this helped!


Neutrality Act<span> of </span>1939<span>. ... Roosevelt prevailed over the isolationists, and on November 4 the </span>Neutrality Act<span> of </span>1939<span> was </span>passed<span>, allowing for arms trade with belligerent nations (Great Britain and France) on a </span>cash-and-carry basis<span>, thus in effect ending the arms embargo.</span>
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How is synthesis and replacement reactions related?
Fittoniya [83]

Answer:

A synthesis reaction occurs when two or more reactants combine to form a single product. ... Replacement reactions occur when elements switch places in compounds. In a single replacement reaction, one element takes the place of another in a single compound. In a double replacement reaction, two compounds exchange elements.

3 0
3 years ago
A person uses a pulley to raise a flag up a 15 meter flagpole. The weight of
GREYUIT [131]

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Explanation:

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3 years ago
A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling
Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is 4.90\times 10^{-3}mol/L

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L

Hence, the concentration of copper fluoride in the solution is 4.90\times 10^{-3}mol/L

4 0
3 years ago
How many moles of H2SO4 are needed to completely neutralize 0.0164 mol KOH
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8 0
3 years ago
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Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abunda
professor190 [17]

The atomic mass of the element would simply be equal to the sum of the weighted average of each isotope, that is:

atomic mass = 59.015 amu * 0.717 + 62.011 amu * (1 – 0.717)

<span>atomic mass = 59.863 amu</span>

4 0
3 years ago
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