Graph a system of two equations that has a single solution of -2,-3

Select an operation to make the equation true.

MrRa [10]

Add. I’m not sure because there is a - besides the 15.

Explanation - 12 + 15 = 27.

Hopefully this helps. Have a blessed one. God loves you. ☺️

3 0

3 years ago

Look at the figure, FHJM. find the length of HJ

Nat2105 [25]

Answer:

$HJ=42\ m$

Step-by-step explanation:

we know that

In a parallelogram opposite sides are equal and parallel

The figure FHJM is a parallelogram

so

$FH=JM=36\ m$

$HJ=FM=42\ m$

therefore

$HJ=42\ m$

6 0

3 years ago

Which statement follows from the given theorem? Theorem: The diagonal of a parallelogram divides it into two congruent triangles

Ivenika [448]

Answer:

SSS

Step-by-step explanation:

the dividing line would give the triangles the same length for one side, the side it divided, and then it says the triangles are congruent, meaning they are both the same triangle.

8 0

4 years ago

which table represents viable solutions for y=5x, where x is the number of tickets sold for the school play a y is the amount of

STALIN [3.7K]

Given:

The given equation is:

$y=5x$

Where x is the number of tickets sold for the school play a y is the amount of money collected for the tickets.

To find:

The correct table of values from the given options.

Solution:

We know that the number of tickets and amount of money collected for the tickets cannot be negative. So, options A and B are incorrect.

We have,

$y=5x$

For $x=0$ ,

$y=5(0)$

$y=0$

For $x=10$ ,

$y=5(10)$

$y=50$

For $x=51$ ,

$y=5(51)$

$y=255$

For $x=400$ ,

$y=5(400)$

$y=2000$

In option C, all the ordered pairs (0,0), (10,50), (51,255), (400,2000) are in the table. So, option C is correct.

For $x=65$

$y=5(65)$

$y=325$

Since the ordered pair (65,350) does not satisfy the given equation, therefore the option D is incorrect.

Hence, the correct option is C.

8 0

3 years ago

The statistics of nequals22 and sequals14.3 result in this 95% confidence interval estimate of sigma: 11.0less thansigmaless t

dimulka [17.4K]

Answer: no, the confidence interval for the standard deviation σ cannot be expressed as 15.7 $\pm$ 4.7

There are three ways in which you can possibly express a confidence interval:

1) inequality
The two extremities of the interval will be each on one side of the "less then" symbol (the smallest on the left, the biggest on the right) and the symbol for the standard deviation (σ) will be in the middle:
11.0 < σ < 20.4
This is the first interval given in the question and it means that the standard deviation can vary between 11.0 and 20.4

2) interval
The two extremities will be inside a couple of round parenthesis, separated by a comma, always the smallest on the left and the biggest on the right:
(11.0, 20.4)
This is the second interval given in the question.

3) point estimate $\pm$ margin of error
This is the most common way to write a confidence interval because it shows straightforwardly some important information.
However, this way can be used only for the confidence interval of the mean or of the popuation, not for he confidence interval of the variance or of the standard deviation.

This is due to the fact that in order to calculate the confidence interval of the standard variation (and similarly of the variance), you need to apply the formula:
$\sqrt{ \frac{(n-1) s^{2} }{\chi^{2}_{\alpha / 2} } } \leq \sigma \leq \sqrt{ \frac{(n-1) s^{2} }{\chi^{2}_{1 - \alpha / 2} } }$

which involves a χ² distribution, which is not a symmetric function. For this reason, the confidence interval we obtain is not symmetric around the point estimate and the third option cannot be used to express it.

4 0

3 years ago