Can you please paste a picture of the triangle? I am happy to help, but I need to see the triangle. :-)
Answer:
The solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Step-by-step explanation:
First, we need to separate the modulus from the rest of equation. So
3-l4-nl>1
-|4-n|>1-3
-|4-n|>-2
Multiplying everything by -1.
|4-n|<2
How to solve:
|x| < a means that -a<x<a
In this question:
|4-n|<2
-2<4-n<2
This means that:
4 - n > -2
-n > -6
Multiplying by -1
n < 6
And
4 - n < 2
-n < -2
Multiplying by 1
n > 2
Intersection:
Between n > 2 and n < 6 is 2 < n < 6
So the solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Answer:
f(g(x)) = x^4 + 12x^3 + 14x^2 -132x + 123
Step-by-step explanation:
Here, we simply will place g(x) into f(x)
So every x in f(x) is replaced by g(x)
Thus, we have;
(x^2 + 6x + 11)^2 + 2
= (x^2+6x-11)(x^2 + 6x -11) + 2
= x^4 + 6x^3 -11x^2 + 6x^3 + 36x^2 - 66x -11x^2 -66x + 121 + 2
= x^4 + 12x^3 + 14x^2 -132x + 123
For the first one:
The radian of 60º is 1.047. you just have to find one that has the same value, which would be 
/3. (the last choice).
for the second one:
you do it the other way. The answer is 45 degrees.
Answer:
The answer is below
Step-by-step explanation:
When you refer to a normal vector you mean the form a*x + b*y + c*z = d, if that's the case then it's not unique in the nose because it gives you its normal vector. Taking into account that uniqueness only supports multiplicative constants, which means that you can multiply the equation with whatever you want, that is, it remains the same
