The given inequality is
![| 9x+ 10 |](https://tex.z-dn.net/?f=%20%7C%209x%2B%2010%20%7C%20%3C15%20)
First we need to remove the absolute sign , and when we do so , we will get a compound inequality, that is
![-15< 9x+10 < 15](https://tex.z-dn.net/?f=%20-15%3C%209x%2B10%20%3C%2015%20)
To solve for x, first we need to get rid of 10. and for that, we have to do subtraction
![-15-10](https://tex.z-dn.net/?f=%20-15-10%3C9x%3C15-10%20%5C%5C%20-25%20%3C%209x%20%3C5%20)
Now we need to get rid of 9, and for that, we do division
![\frac{-25}{9}< x< \frac{5}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-25%7D%7B9%7D%3C%20x%3C%20%5Cfrac%7B5%7D%7B9%7D%20)
So the required solution is
![( \frac{-25}{9} , \frac{5}{9})](https://tex.z-dn.net/?f=%20%28%20%5Cfrac%7B-25%7D%7B9%7D%20%2C%20%5Cfrac%7B5%7D%7B9%7D%29%20)
Answer:
(3x^2 + 2)(x + 4).
Step-by-step explanation:
3x3 + 12x2 + 2x + 8
3x^2(x + 4) + 2(x + 4) The x + 4 is common to the 2 groups so we have:
(3x^2 + 2)(x + 4).
I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.
</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct
</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct
</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>
Answer: the answer is A.
Step-by-step explanation:
All I did was type it into the internet and it gave me 5p+2w+2