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mina [271]
2 years ago
7

Determine whether each of the following triangles is a right-angled triangle

Mathematics
1 answer:
Fantom [35]2 years ago
4 0

Answer:

Yes

Step-by-step explanation:

To determine if this is a right triangle, use the pythagorean theorem and see if a^2 + b^2 is equal to c^2.

a^2 + b^2 = c^2

12^2 + 16^2 = 20^2

Evaluate the exponents.

144 + 256 = 400

Add them together.

400 = 400

Since a^2 and b^2 add up to equal c^2, this is a right triangle.

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Irina-Kira [14]
5*18=90
3*x=90
X=90/3
X=30
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3 years ago
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How do you find the ratio of 2:5...
LuckyWell [14K]

Answer:

total number of parts of a 2:5 ratio are 7 as 2+5 = 7

let us assume are number to be 49

the first part will be 49/7 × 2 = 14

the second part will be 49/7 × 5 = 35

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It’s not a question on here but I think you solve for x
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4.56

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2 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
10 months ago
Which expression is equivalent to (10x)^-3?
kolbaska11 [484]
(10x)^ (-3)
= 1/ [(10x)^3]
= 1/ [10^3* x^3]
= 1/ (1000x^3)

The final answer is 1/ (1000x^3), and I don't think there is a correct option to choose from. ( option c would be correct if it were written with round brackets)

Hope this helps~
4 0
3 years ago
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