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3 years ago

12

In the solution of the equation 5 + 3x = -2x + 9, 2x is added to the equation first. Which of the following should be done next?

1 answer:

puteri [66]3 years ago

5 0

You should subtract 5 from both sides next.

Adding 2x to both side will give you the following.

5 + 5x = 9

And since you got all the variable terms to the left, you want all the constant terms to the right. You do that by subtracting 5 from both sides. This gives you the below statement.

5x = 4

You can then divide to solve.

x = 4/5 or .8

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A 10% booking fee is added to the ticket price (I'm guessing 10% is added for each ticket)

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10% of 15 = 1.5

10% of 10 = 1

find the total price for the 4 adult tickets he buys and 2 child tickets:

(15 +1.5) × 4 = 66

(10 + 1) × 2 = 22

66 + 22 = 88

1.5% will then be added if he lays by credit card :

1.5% of 88 = 1.32

total :

88 + 1.32 = 89.32

He pays a total of £89.32

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4 years ago

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(2x^9y^n) (4x²y^10)-8x^11 y^20 i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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2 years ago

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Dennis_Churaev [7]

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<h2>25</h2>

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The rate of change of number of tree y on x branches of a tree is expressed as shown;

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Δy is the change in number of leaves between 3 and 4

Δx is change in number of branches between 3 and 4

m = Δy/Δx = y₂-y₁/x₂-x₁

From table between 3 and 4, y₂ = 100, y₁ = 75, x₂ = 4, x₁ = 3

m = 100-75/4-3

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<em>Hence the rate of change between 3 and 4 branches is 25</em>

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3 years ago

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Evgesh-ka [11]

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3 years ago

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