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Scrat [10]
4 years ago
14

What is the simplified form of 64x^16

Mathematics
1 answer:
Alenkinab [10]4 years ago
4 0
It can be written as √64·√x¹⁶ = 8x⁸, so answer B.
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Help pls I’ll give points
alukav5142 [94]
It is the answer number 2
3 0
3 years ago
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The coordinates of the vertices of AABC are A(2,5), B(6, -1), and C(-4,-2). Find the perimeter of AABC, to the nearest tenth.​
ValentinkaMS [17]

Answer:

S...tep-by-step explanation:

5 0
3 years ago
Asphere has a diameter of 10 in. What is the volume of the sphere?
Pavel [41]

Answer:\frac{500}{3}π in^{3}

Step-by-step explanation: diameter=10 in

radius=\frac{diameter}{2}=\frac{10}{2}=5 in

volume=\frac{4}{3}r^{3}

=\frac{4}{3}    X 5^{3}  x π =\frac{500}{3}π in^{3}

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4 years ago
Yummy Donuts gave three dozen chocolates donuts and four dozens jelly donuts to the school. How many donuts did they give?
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4 0
3 years ago
Determine the coordinates of the intersection of the diagonals of square ABCD with verticals A(-4,6), B(5,6) C(4,-2), and D(-5,-
timama [110]

Given:

Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).

To find:

The intersection of the diagonals of square ABCD.

Solution:

We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.

In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.

We can find midpoint of either AC or BD because both will result the same.

Midpoint of A(-4,6) and C(4,-2) is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+4}{2},\dfrac{6+(-2)}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{6-2}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{4}{2}\right)

Midpoint=\left(0,2\right)

Therefore, the intersection of the diagonals of square ABCD is (0,2).

4 0
3 years ago
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