Solve these systems for (x,y,z) -x+y+z=4 -x+2y-3z=-6 2x-4y+8z=18

1 answer:

4 0

Multiply the first equation by -1 and add it to the second one, getting
y-4z=-10

Multiply the first equation by 2 and add it to the third one, getting -2y+10z=26

As you can see, we eliminated x and turned it into two equations with 2 variables.

Multiply the first new equation by 2 and add it to the second one to get
2z=6 and z=3. Substitute it in to -2y+10z=26 to get y=2 and substitute it into -x+y+z=4 to get x=1

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