Answer:
Step-by-step explanation:
-2x + 3y – 4z = 8 ----------------(I)
5x – 3y + 5z = -8 -----------------(II)
7x – 3y + 3z = 8 ------------------(III)
Add equation (I) & (II) and thus y will be eliminated
(I) -2x + 3y – 4z = 8
(II) <u>5x – 3y + 5z = -8</u> {Add}
3x + z = 0 ------------------------(A)
Multiply equation (II) by (-1) and then add with equation (III). Thus y will be eliminated.
(II) * (-1) -5x + 3y - 5z = +8
<u>7x – 3y + 3z = 8</u> {Add}
2x -2z = 16 ---------------(B)
Multiply equation (A) by 2 and then add. Thus z will be eliminated and we will get the value of x
(A) * 2 6x + 2z = 0
(B) <u>2x - 2z = 16</u> {Add}
8x = 16
Divide both sides by 8
x = 16/8
x = 2
Plugin x = 2 in equation (A)
3x + z = 0
3*2 + z = 0
6 + z = 0
z = -6
Plug in x = 2 and z = - 6 in equation (I)
-2x +3y - 4z = 8
-2*2 + 3y - 4*(-6) = 8
-4 + 3y + 24 = 8
3y + 20 = 8
3y = 8 - 20
3y = -12
y = -12/3
y = -4
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To solve this problem you must apply the proccedure shown below:
1. Yoy have that the <span>rectangular tank has the following dimensions:
Length=3 inches
Widht=4 inches
Height=5 inches
2. Then, its volume is:
V1=LxWxH
V1=3 inchesx4 inchesx5 inches
V=60 inches</span>³
3. The sides of the <span>solid metal cube are of 3 inches, therefore, its volume is:
V2=s</span>³
V2=(3 inches)³
V2=27 inches³
4. T<span>he volume, in cubic inches, of water that the tank can now hold is:
Vt=V1-V2
Vt=60 inches</span>³-27 inches³
Vt=33 inches³
Answer:f(3) = 23
Step-by-step explanation:
2(3)² + 5√(3 - 2)
f(3) = 2(9) + 5√(1)
f(3) = 18 + 5(1)
f(3) = 18 + 5
f(3) = 23
