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Ronch [10]
3 years ago
14

How do I find the slope from a table if the value added onto each (x,y) value is different? Please help!!! I need the slope!

Mathematics
1 answer:
Bess [88]3 years ago
5 0
ANSWER:
________

Line q = 3
Line v = -1/2

FORMULA
__________

y2 - y1 / x2 - x1

EXPLANATION:
_____________

First, we need to find the slope for line a only

We need to select two points from line q. The ones I selected are (-3,18) and (2,33)

y2 = 33
y1 = 18

x2 = 2
x1 = -3

33 - 18 = 15
2 - -3 = 5

15/5 = 3

Next, we need to find the slope for line v.

The two points I picked are (0,8) and (10,3)

y2 = 8
y1 = 3

x2 = 0
x1 = 10

8 - 3 = 5
0 - 10 = -10

5/-10 = -1/2

And that’s how you get your answer :)

PUN OF THE DAY
_______________

Why did Adele cross the road? To say hello from the other side.

I hoped this helped! And have a •AMAZING• day :3
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Step-by-step explanation:

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il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify [\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2   and to find the value of s in x^s.

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}
Comparing with x^S
s = -16/3


Thus, the required value of the s = -16/3. None of these are correct.

Learn more about simplification here: brainly.com/question/12501526

#SPJ1

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