The major axis of the eclipse is 12 units long
The given parameters can be represented as:


See attachment for illustration
To solve this question, we make use of the following theorem
The distance between a point and the foci sums up to the major axis
This translates to:



Answer:
the distance of the Bird (B) from the plane (P) is = 10779 ft
Step-by-step explanation:
From the given information:
a diagrammatic representation is attached below for better understanding and solution to the question.
From the diagram;
Let the Bird (B) be represent as A
The plane (P) be represented by B
The observer be represented by O
and the tower T be represented by C
we will see that:

Also;

AO = BC = 7000
Let consider the trigonometry of triangle BAO
tan θ = opposite/adjacent
tan 33° = 7000/x
0.6494 = 7000/x
x = 7000/0.6494
x = 10779.18
x = 10779 ft ( to the nearest whole number)
Thus; the distance of the Bird (B) from the plane (P) is = 10779 ft
Answer:
1395in^3
Step-by-step explanation:
First find the volume of the cuboid, 15in x 9in x 7in = 945in^3
Then find the volume of the rectangular pyramid using the formula V=lwh/3, the total height is 17in so subtract the height of the cuboid from the total height, giving you 10in.
V=(15in)(9in)(10in)/3 = 450in^3
450in^3 + 945in^3 = 1395in^3
Area abc def cuase its 126-72+28=82 so abc def