If c = 8 and d = -5:
a) c - 3 = 8 - 3
= 5
b) 15 - c = 15 - 8
= 7
c) 3(c + d) = 3(8 + (-5))
= 3*3
= 9
d) 2c - 4d = 2(8) - 4(-5)
= 16 + 20
= 36
e) d - c^2 = -5 - (8)^2
= -5 - 64
= -69
f) 2d^2 + 5d = 2(-5)^2 + 5(-5)
= 50 - 25
= 25
All points along the circle with be the distance of the radius from the center...so the radius can be found using the Pythagorean Theorem..
r^2=(4-1)^2+(6-2)^2
r^2=9+16
r^2=25
r=5
The equation of the circle can be expressed as:
r^2=(x-h)^2+(y-k)^2 where (h,k) correspond to the center of the circle, (2,1) in this case.
(x-2)^2+(y-1)^2=25
if you wanted it in a more standard form...
(y-1)^2=25-(x-2)^2
(y-1)^2=25-x^2+4x-4
(y-1)^2=-x^2+4x+21
y-1=(-x^2+4x+21)^(1/2)
y=1(+/-)(-x^2+4x+21)^(1/2)
Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.
Answer:
D
Step-by-step explanation:
speed = space/time
24/4.3 = 5.6 ft/s
You could do:
1 mile : 1,760 yards.
So, you would multiply 1790 times 2 and get 3520. The closest thing to 4500 yards is 3520.
So you get 2 miles and 980 yards.
