Th matrix is missing. The matrix is :
![\begin{bmatrix}1 &-4 &4 \\ -4 &16 & 4 \end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D1%20%26-4%20%20%264%20%5C%5C%20-4%20%2616%20%20%26%204%20%5Cend%7Bbmatrix%7D)
Solution :
The column of the matrix are
,
, ![\begin{bmatrix}4\\ 4\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D4%5C%5C%204%5Cend%7Bbmatrix%7D)
Now each of them are vectors in
. But
has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.
Therefore, the column of the given matrix does not form the
as the set contains
than there are entries in each vector.
Therefore, option (D) is correct.
The correct answer is the first one
Answer:
I don't know it's very hart
Answer:
It's 1/2 I found this out by subtracting 3/4 - 1/3= 5/12 and if you put that into a decimal it would be .41. So that 1/4= .25 and 1/2= .50. You could figure out that it’s closed to 1/2.