Answer:
Same question a just took, answer is clockwise 270 degress, please give me brailiest
Step-by-step explanation:
It is given in the question that ray QT bisects ㄥPQR.
And we have to find the measurement of angle PQR.
Since QT bisects angle PQR, therefore measurement of angle RQT and angle PQT are equal. That is
Substituting the value of x, we will get
And measurement of angle PQR is twice of the measurement of angle RQT, that is
Answer: ¢=68.2
Step-by-step explanation:
y(t) = 2sin4πt + 5cos4πt
Let , x = Asin¢ = 5
y = Acos¢ = 2
A = sqrt(5²+2²)
A= 5.39
y(t) = Acos¢sin4πt + Asin¢cos4πt
From Trigonometry rule,
y(t)= Asin(wt +¢)
tan¢ = 5/2
¢ = arctan(5/2) = 68.2°
y(t) = 5.39sin(wt + 68.2)
Where w = 4π
The angle ¢= 68.2°
Answer:
D
Step-by-step explanation:
If f(x) = 4x ^ 2 - 3 and g(x) = x + 1 , find (f - g)(x)
A. 4x ^ 2 - x - 2
B. x - 4x ^ 2 - 2
C. 4x ^ 3 - 3
D. 4x ^ 2 - x - 4
(f - g)(x) = f(x) - g(x)
4x ^ 2 - 3 - (x + 1 ) Multiply the brackets by the negative.
4x ^ 2 - 3 -x - 1 Add like terms.
4x ^ 2 - x - 4 Final Answer
