Answer with Step-by-step explanation:
Since we have given that
a + b = c
and a|c
i.e. a divides c.
We need to prove that a|b.
⇒ a = mb for some integer m
Since a|c,
So, mathematically, it is expressed as
c= ka
Now, we put the above value in a + b = c.
So, it becomes,
a=mb, here, m = k-1
Hence, proved.
Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
Answer:
Table 3
Step-by-step explanation:
Check table three;
Since the left hand limit is not equal to the right hand limit
, the limit as x approaches to 2 does not exist.
Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2
