Back then, movies were black and white because they had cameras that could only see black and white. In the late 1900's and early 2000's, they developed color cameras. But the common resolution and screen size was 640x480 or 4:3. Nowadays, in the late 2000's and early 2010, the widescreen format was more commonly used for many reasons. Today, the common colors are RGB 1M colors, and the resolution is 16:9. Some movies like to go even farther, like me, and use 21:9,which is super widescreen. That is more immersive than 16:9, and gives the watcher a wider, better experience.
<em>hoping</em><em> that</em><em> </em><em>it </em><em>was </em><em>helpful</em><em> to</em><em> </em><em>you</em>
<em>plz </em><em>mark </em><em>me </em><em>as </em><em>brainlist</em><em> answer</em>
Records for the first one and table for the second one
Answer:
A) work study program
Explanation:
Because you need experience and scholarships don't always pay, so this is the best choice.
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
