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Dahasolnce [82]
3 years ago
6

Write an inequality and use substitution to solve the following problem:

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

They already spent $2000, and they only had $5100

Subtract

5100 - 2000 = 3100

$3,050 is your answer, because it is the only one that is less than 3100

hope this helps

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Q = 3x + 9x? idk this one lol
Serjik [45]

Answer:

<em>q</em> = 12<em>x</em>

Step-by-step explanation:

<em>q</em> = 3<em>x</em> + 9<em>x</em>

Combine like terms

<em>q</em> = 12<em>x</em>

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Rob Polanski is a tractor salesman. Last week his total sales amounted to $38,642.00, and he received $2,704.94 in commission. W
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Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
A bookstore sells textbooks for $80 each and notebooks for $4 dollars each. The bookstore would like to sell $800 in merchandise
mariarad [96]

Answer: 8 textbooks

Step-by-step explanation:

Sold 40 notebooks = 40 x $4 = $160

$800 - $160 = $640 left to sell

$640/$80 (cost of textbook) = 8 textbooks need to be sold

3 0
3 years ago
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