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3 years ago

-0.5 • 4 to the 18 exponent

Mathematics

2 answers:

worty [1.4K]3 years ago

8 0

Answer:

262,144

Step-by-step explanation:

(-0.5 * 4)^18

(-2)^18

262,144

Answer: 262,144

Ivahew [28]3 years ago

8 0

Answer:

262144

Step-by-step explanation:

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c) Your parents have been advised to save 5% of their income for your college education, which would include money for housing,

Gennadij [26K]

In one year they would have saved up $2447.40 for your education
convert 5% into a decimal then divide by 100.

Hope this helped :)

3 0

3 years ago

Read 2 more answers

25/4=x/10 please help thanks

Marta_Voda [28]

Answer:

125/2 or 62.5 or 62 1/2 (x=)

Step-by-step explanation:

25/4=x/10 multiply everything by 20

25*20/4=20x/10 simplify

25*5=2x simplify

125=2x divide on both sides

125/2 or 62.5 or 62 1/2=x

7 0

4 years ago

At a toll booth, an attendant found that for every 5 vehicles that passed through the toll, 2 were trucks.

kompoz [17]

Answer:

Step-by-step explanation:

5-2=3

other vehicles:Trucks::3:2

3 0

4 years ago

Please need help (s + 12) + (3s - 8)

umka21 [38]

s+12+3s−8=
s+12+3s+−8
Combine Like Terms
s+12+3s+−8=
(s+3s)+(12+−8)=
4s+4

6 0

4 years ago

Read 2 more answers

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

4 years ago