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photoshop1234 [79]

3 years ago

15

What are the first five sequences to the equation f(1)=2/3,f(n)=f(n-1)x3/2

1 answer:

iren [92.7K]3 years ago

7 0

Answer:

2/3,1,3/2,9/4,27/8

Step-by-step explanation:

f(1)=2/3

f(n)=f(n-1)×3/2

f(2)=f(2-1)×3/2=f(1)×3/2=2/3×3/2=1

f(3)=f(3-1)×3/2=f(2)×3/2=1×3/2=3/2

f(4)=f(4-1)×3/2=f(3)×3/2=3/2×3/2=9/4

f(5)=f(5-1)×3/2=f(4)×3/2=9/4×3/2=27/8

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dangina [55]

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5 0

3 years ago

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express each of the following as product of its prime factors, giving your answer in expanded form. a) 24. b) 63. c) 84. d) 150

Alborosie

To answer this question, you can use a factor tree, or the table thing (I forgot what it’s called.)
You divide the number by one of its PRIME factors, until there is only one left. The numbers you divided it by are written as shown.
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3 years ago

Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0

3 years ago

An assistant at an animal shelter wants to know the typical age of dogs admitted to the shelter. the shelter has admitted 353 do

Nikitich [7]

Step-by-step explanation:

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2 years ago

If a 35 ft rope is cut into two sections with one section 6 times as long as the other section, how long is the shorter piece?

Yuliya22 [10]

The smallest piece is 5ft, 5x6+5=35

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3 years ago

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