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makkiz [27]
2 years ago
12

The ratio of the surface area of two cubes is 49:81. Find the ratio of there volumes.​

Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
7 0

Answer:

343 : 729

Step-by-step explanation:

A cube is made up of 6 square faces. If each face has a side length of a, we can find the surface area of that cube with the formula A=6a^2, since we'll have 6 faces with area a². Let's call the edge length of the first cube a and the edge length of the second cube b. The ratio between their surface areas is then 6a² : 6b², or simply a² : b². If we compare this to our given ratio 49 : 81, we can see that a² = 49 and b² = 81, or, square rooting both equations, a = 7 and b = 9.

The volume of a cube with a side length a is a³, so the ratio between our cubes here must be a³ : b³. Using the values for a and b we just found, this ratio becomes 7³ : 9³, which we can simplify to 343 : 729.

tia_tia [17]2 years ago
4 0

Answer:

343 : 729

Step-by-step explanation:

If the ratio of the sides of a cube = a : b , then

ratio of areas = a² : b² and

ratio of volumes = a³ : b³

Given ratio of areas = 49 : 81, then

ratio of sides = \sqrt{49} : \sqrt{81} = 7 : 9 , so

ratio of volumes = 7³ : 9³ = 343 : 729

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\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n

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\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0

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\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}

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k=0 \implies n=0 \implies a_0 = a_0

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a_{n=2k} = \dfrac{a_0}{(2k)!}

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