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makkiz [27]
3 years ago
12

The ratio of the surface area of two cubes is 49:81. Find the ratio of there volumes.​

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0

Answer:

343 : 729

Step-by-step explanation:

A cube is made up of 6 square faces. If each face has a side length of a, we can find the surface area of that cube with the formula A=6a^2, since we'll have 6 faces with area a². Let's call the edge length of the first cube a and the edge length of the second cube b. The ratio between their surface areas is then 6a² : 6b², or simply a² : b². If we compare this to our given ratio 49 : 81, we can see that a² = 49 and b² = 81, or, square rooting both equations, a = 7 and b = 9.

The volume of a cube with a side length a is a³, so the ratio between our cubes here must be a³ : b³. Using the values for a and b we just found, this ratio becomes 7³ : 9³, which we can simplify to 343 : 729.

tia_tia [17]3 years ago
4 0

Answer:

343 : 729

Step-by-step explanation:

If the ratio of the sides of a cube = a : b , then

ratio of areas = a² : b² and

ratio of volumes = a³ : b³

Given ratio of areas = 49 : 81, then

ratio of sides = \sqrt{49} : \sqrt{81} = 7 : 9 , so

ratio of volumes = 7³ : 9³ = 343 : 729

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Step-by-step explanation:

(2a^2 / b)  x ( a / b^2) ^2

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= 2a^4 / b^5

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Molodets [167]
Hi there! The answer is A.

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Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

7 0
2 years ago
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