Answer:
Step-by-step explanation:
Composition of two functions f(x) and g(x) is represented by,
(fog)(x) = f[g(x)]
If a function is,
f(x) = (-6x - 8)² [where x ≤ 
]
Another function is the inverse of f(x),
Now composite function of these functions will be,
![(fof^{-1})(x)=f[f^{-1}(x)]](https://tex.z-dn.net/?f=%28fof%5E%7B-1%7D%29%28x%29%3Df%5Bf%5E%7B-1%7D%28x%29%5D)
= ![[-6(\frac{\sqrt{x}+8}{6})-8]^{2}](https://tex.z-dn.net/?f=%5B-6%28%5Cfrac%7B%5Csqrt%7Bx%7D%2B8%7D%7B6%7D%29-8%5D%5E%7B2%7D)
= ![[-\sqrt{x}+8-8]^2](https://tex.z-dn.net/?f=%5B-%5Csqrt%7Bx%7D%2B8-8%5D%5E2)
= 
= x
Therefore,
Answer:28
Step-by-step explanation:103-20-20-25-10,will be equaled to (28)
This is a relation but not a function.
Functions must have that there is a unique y for a given x, which clearly doesn't work here because all lines of a given x have 2 y-values. However, it is a relation because there is a given set of points which are defined to be within the set of the ellipse (if it's defined which members of two sets, the range and domain, go together, then you have a relation)
