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Sedbober [7]
3 years ago
10

Which graph represents has a function of x Please hurry its urgent Thank you

Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0

The correct answer would be B

GenaCL600 [577]3 years ago
3 0
<h3>Answer: Graph A (horizontal line in upper left corner)</h3>

This graph is a function because it is impossible to pass a single vertical line through more than one point on this graph. Contrast this with something like graph B, and it is possible to draw a vertical line through more than one point. The same happens with C as well. Graph D is a vertical line, and any vertical line is never a function.

Algebraically, for any input x, there is only one output y assuming x is in the domain. For a graph like choice C, plugging in x = 0 leads to y = -3 and y = 3 at the same time, which shows it is not a function.

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How to find area? will give..
ch4aika [34]

Answer:

Step-by-step explanation:

A=πr2

Circumference = 2πr

20π = 2πr

r=10

π=3.14

A=3.14 * 10^2

=314 cm^2

3 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|&#10;\\\\\\&#10;\begin{array}{lllcclll}&#10;f(x)=&3|&1x&+2|&+4\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
Apply the distributive property to create an equivalent expression.<br><br> (1−2g+4h)⋅5
alex41 [277]

Answer:

Step-by-step explanation:

distribute 5 in parenthesis means you multipy each term by 5

5*1-5*2 g+5*4h = 5-10g+20h

5 0
3 years ago
Once Farid spends 15 minutes on a single level in his favorite video game, he loses a life. He has already spent 10 minutes on t
Zolol [24]

Answer:

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Step-by-step explanation:

Since this is a ratio problem we can simply use the rule of three to solve it. We need to multiply the diagonal values and divide by the remaining value to get the variable which in this case is x (how much life he has already lost)

15 minutes   <=======>   1 life

10 minutes   <=======>   x

(10 * 1) / 15 = x

10 / 15 = x

0.6666 or \frac{1}{3}  = x

Finally, we can see that Farid has lost 0.6666 or \frac{1}{3} in those 10 minutes

7 0
2 years ago
Use elimination method to solve 3x+y=-14 and -2x-y=9
TiliK225 [7]
I hope this helps you



3x+y-2x-y= -14+9


x= -5


-2. (-5) -y=9


10-y=9

y=1
7 0
3 years ago
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