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3 years ago

Which graph represents has a function of x Please hurry its urgent Thank you

Mathematics

2 answers:

Mamont248 [21]3 years ago

7 0

The correct answer would be B

GenaCL600 [577]3 years ago

3 0

<h3>Answer: Graph A (horizontal line in upper left corner)</h3>

This graph is a function because it is impossible to pass a single vertical line through more than one point on this graph. Contrast this with something like graph B, and it is possible to draw a vertical line through more than one point. The same happens with C as well. Graph D is a vertical line, and any vertical line is never a function.

Algebraically, for any input x, there is only one output y assuming x is in the domain. For a graph like choice C, plugging in x = 0 leads to y = -3 and y = 3 at the same time, which shows it is not a function.

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Sean has a collection of coins. One tenth of the coins are from Europe. Thirty-two hundredth are from Asia. The rest are from Af

Tema [17]

Lets write each part, the total will be x:
(1/10)x = Europe
3200 = Asia
x - <span>(1/10)x - 3200 = Africa

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= (320x + 1)/3200
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3 years ago

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5x+10=24-2x what is this called?

Free_Kalibri [48]

This is a one variable equation in algebra.

X = 2

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3 years ago

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Find the value of x when m<2 = x + 64

polet [3.4K]

Answer:

-9

Step-by-step explanation:

The triangle has two sides that are the same, so it is an isosceles triangle. Therefore, the base angles are the same.

Angles of a triangle add up to 180°, so:

70 + (x + 64) + (x + 64) = 180

70 + 2x + 128 = 180

2x = -18

x = -9

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3 years ago

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Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

2 years ago

An aircraft factory manufactures airplane engines. The unit cost (the cost in dollars to make each airplane engine) depends on t

Juliette [100K]

Answer:

Minimum unit cost = 5,858

Step-by-step explanation:

Given the function : C(x)=x^2−520x+73458

To find the minimum unit cost :

Take the derivative of C(x) with respect to x

dC/dx = 2x - 520

Set = 0

2x - 520

2x = 520

x = 260

To minimize unit cost, 260 engines must be produced

Hence, minimum unit cost will be :

C(x)=x^2−520x+73458

Put x = 260

C(260) = 260^2−520(260) + 73458

= 5,858

7 0

3 years ago