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s2008m [1.1K]
3 years ago
11

Combine the like terms to create an equivalent expression: Y- (-3y)

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
Distribute: - (-3y)

You’ll now get y + 3y

Combine like terms and you’ll get 4y

(I maybe wrong but I think this is probably the answer)
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To convert 132 milligrams to grams, you can set up the proportion x/132 mg = 1,000/ 1 g
marin [14]

Answer:

FALSE

Step-by-step explanation: You can convert 132 milligrams by using the KHDUDCM(King Henry Died Unusually Drinking Chocolate Milk) And you will have to add three zeros to 132.  (I might be incorrect)

5 0
2 years ago
Read 2 more answers
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
For the function given state the period f(t) =6sin(3t-pi/6)-1
lapo4ka [179]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now, with that template in mind, let's take a peek at yours

\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}
8 0
3 years ago
A scientist is working with 14 meters of gold wire. How long will the wire be in millimeters?
Tcecarenko [31]
In a meter there are 100 cm.
In 100 cm there are 1000 mm. 

Therefore in 1 meter you have 1000 millimeters. 

Then to find out how many millimeters you have in 14 meters, you just multiply 14 by 1000 to give you 14000 mm.

Final answer= 14 m of gold wire is the equivalent to 14000 mm of wire.
5 0
3 years ago
Read 2 more answers
What is the greatest common factor of 30y^8+10y^4 ?<br><br> 10y^4<br> y^2<br> 10y^8<br> 20y^2
sesenic [268]
<span>I think it's C.10y^8 hope this helps</span>
6 0
3 years ago
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