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IceJOKER [234]
3 years ago
14

6a+2b-6c+4 if a=5,b=3,and c=-1

Mathematics
2 answers:
Arisa [49]3 years ago
8 0

Answer:

46

Step-by-step explanation:

First, start off by substituting the values of a, b, and c, into the equation.

We know a = 5, b = 3, and c = -1, so now substitute.

6a + 2b - 6c + 4

6(5) + 2(3) - 6(-1) + 4

Now that we've substituted the values, we can solve the equation.

6(5) + 2(3) - 6(-1) + 4

30 + 6 + 6 + 4

= 46

So, the answer is 46.

I hope this helps! ôヮô

lys-0071 [83]3 years ago
6 0

Answer:

46

Step-by-step explanation:

All you need to do is subsitute the variable with what it says the number is.

Let's first start out with 6a from the equation.  We know that a= 5, so that means it wants you to multiply 6 by 5, which is 30.

Now let's do 2b.  It says b= 3, so do 2 times 3.  It equals 6.

<u>So far we have 30+6-6c+4</u>

Let's do -6c.  We know that c= -1, so let's multiply -1 and -6.  Negative and negative equals positive.  And 6 times 1 is 6.  So the outcome is positive 6.

We got <u>30+6+6+4</u>

Solve.  

30+6= 36

36+6= 42

And 42+4= 46.  :)

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