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viktelen [127]
3 years ago
12

cary's barbecue sauce recipe calls for 2 2/3 cups of water for every 8 pints of tomato sauce how menu cups of water does cary us

e when she make barbecue sauce with 1 pint of tomato sauce​
Mathematics
2 answers:
Alika [10]3 years ago
7 0

Answer:

1/3 of a cup

Step-by-step explanation:

Just do (2 2/3)/8

Anna [14]3 years ago
3 0
1/3 of a cup hope that helps
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What is the coefficient of x2 in this trinomial?
Scorpion4ik [409]

Answer:1

Step-by-step explanation:

(x+2)(x+3)

x^2+3x+2x+6

x^2+5x+6

Therefore the coefficient of x^2 is 1

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Answer:

B

Step-by-step explanation:

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Solve 4e^2x-3=12 please help
Anestetic [448]

4*e^{2x} -3 = 12

Step 1:

Here we have -3 in subtraction on the left side, so when we take it to the right we apply opposite operation of subtraction that is addition.

4*e^{2x} = 12+3

4*e^{2x} = 15

Step 2:

Next we have 4 in multiplication on left side, so dividing right side by 4,

e^{2x} = 15/4

e^{2x} = 3.75

Step 3:

taking log on both sides

ln ( e^{2x}) = ln(3.75)

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Step 4:

Dividing right side by 2,

x= ln (3.75) /2 = 0.66088

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3 years ago
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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

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liubo4ka [24]

Answer:

no because 2/3 is greater

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