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trapecia [35]
3 years ago
12

Prove the the triangle with vertices a(−2,4,0), b(1,2,−1) and c(−1,1,2) is regular.

Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0
See the offered decision:
one way is to calculate (and compare) lengths of AB, AC and BC:
AB²=(-2-1)²+(4-2)²+(0+1)²=14;
AC²=(-2+1)²+(4-1)²+(0-2)²=14;
BC²=(-1-1)²+(1-2)²+(2+1)²=14.
AB=AC=BC ⇒ the triangle is regular.
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Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

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y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

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<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

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Answer:

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