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Natasha_Volkova [10]
3 years ago
10

Give the difinition, formula, and example problem of permutation, combination & probability... please asap huhu I'll mark yo

u as the brainliest if can do this ​
Mathematics
2 answers:
SSSSS [86.1K]3 years ago
7 0

Answer:

Answer:

Permutation:

In mathematics, a permutation of a set is, loosely speaking, an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements. The word "permutation" also refers to the act or process of changing the linear order of an ordered set.

Formula:

nPr=\frac{n!}{(n-r)!}

Example:

Permutations are the different ways in which a collection of items can be arranged. For example, the different ways in which the alphabets A, B and C can be grouped, taken all at a time, are ABC, ACB, BCA, CBA, CAB, BAC. Note that ABC and CBA are not the same as the order of arrangement is different.

Combination:

In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.

Formula:

nCr=\frac{n!}{r!(n-r)!}

Example:

Combination: Picking a team of 3 people from a group of 10.

C(10,3) = 10!/(7! * 3!) = 10 * 9 * 8 / (3 * 2 * 1) = 120.

Probability:

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates the impossibility of the event and 1 indicates certainty.

Formula:

Conditional Probability P(A | B) = P(A∩B) / P(B)

Bayes Formula P(A | B) = P(B | A) ⋅ P(A) / P(B)

Example:

Probability is the likelihood or chance of an event occurring. For example, the probability of flipping a coin and its being heads is ½, because there is 1 way of getting a head and the total number of possible outcomes is 2 (a head or tail). We write P(heads) = ½.

Mariulka [41]3 years ago
5 0

<em><u>~permutation~</u></em>

Permutation is a term that in mathematics refers to several different meanings in different areas.

Permutation can be permutation with repetition and permutation without repetition.

nPr=

(n−r)!

n!

<em><u>~</u></em><em><u>Permutation</u><u> </u><u>without</u><u> </u><u>repetition</u></em><em><u>~</u></em>

Permutation means to combine the default elements in all possible ways so that each group contains all the default elements.

The number of permutations of a set of n different elements is equal Pn=n×(n-1)×...×2×1=n!

<em><u>~</u><u>Permutation with repetition</u><u>~</u></em>

If between n given elements there are k1 equals of one kind, k2 equals of another kind,..., ky equals of rth kind, we speak of permutations with repetition.

<em><u>~combinations without repetition~</u></em>

In many counting problems, the order of the selected elements is not important.

Each choice of r different elements of an n-member set determines one of its subsets that has r elements, we call it a combination of r-th class without repetition of n elements.

nCr=

r!(n−r)!

n!

<em><u>~combinations with repetition~</u></em>

Repetition combinations are combinations in which elements can be repeated.

<em><u>~Variations without repetition~</u></em>

A variation of the r-th class in an n-membered set is each ordered r-torque of different elements.

(We can determine this number using the principle of consecutive counting).

<em><u>~Variations with repetition~</u></em>

If the elements in ordered r-tuples can be repeated we are talking about variations with repetition.

(We can determine this number using the principle of consecutive counting).

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sp2606 [1]

Answer:8

Step-by-step explanation:

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2 years ago
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
3 years ago
Add 1/ 10 11/100 and select the correct answer. all i got is 12/100 pleaseee help i tried
Vesnalui [34]
I think it's 21/100 because I found the common denominator by multiplying by ten so I multiplied 1 times ten to get 10. Does that help?
3 0
3 years ago
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