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telo118 [61]
3 years ago
6

A teacher wants to find out the average number of weekly reading hours of her students. She noted the number of reading hours of

5 of her students as shown below: 6, 2, 5, 3, 4 Which measure of central tendency is most appropriate for this situation, and what is its value? Only the median; 5 Only the mean; 4 Either the mean or median; both are 5 Either the mean or median; both are 4
Mathematics
2 answers:
JulsSmile [24]3 years ago
5 0

Both mean and median are 3.

the mean is calculated by adding the values up and dividing by the number of values. the median is calculated by ordering them from least to greatest and finding the middle value (sometimes there are two).

Hope I helped.

postnew [5]3 years ago
5 0

Answer:

The answer is mean or  median both are 4

Step-by-step explanation:the answer is the  D

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olga2289 [7]
X=50

all four of a squares angles are 90°

90•3=270

270-20=250

250/5=50

x=50
4 0
2 years ago
Help please!!!!!!!!!!!!!!!
Likurg_2 [28]
First, find the area of the whole square.

Area= Base times height= 48 times 96 = 4608

Next, find the area of ONE circle. The diameter is 12, so the radius would be 6

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Next multiply by 3, since there are 3 circles.

113.04 times 3 =339.12

Subtract this value from the total area (4608)

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3 years ago
What is the nth term of 0 3 8 15 24 35 48
Natasha2012 [34]
So 3+5=8
8+7=15
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4 0
3 years ago
In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean
Nastasia [14]

Answer:

a) \bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

b) ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n=80 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

For this case we can calculate the mean like this:

\bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

Part b

For this case is the sample size is doubled the margin of error would be:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

5 0
3 years ago
Graph the linear equation y=-1/5x+3​
adoni [48]

Answer:

ur answer is a

4 0
3 years ago
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