What is 16tons what pounds
2 answers:
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Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with
Expected number before 1 defective(n = 1). So
Variance is:
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
9514 1404 393
Answer:
10s place
Step-by-step explanation:
When you line up the three digits of the divisor with the three most significant digits of the dividend, you see that the least significant digit of the divisor lines up with the dividend digit that is in the 10s place.
The first (most-significant) quotient digit will be in the 10s place.
_____
In the attached, the left-most non-zero quotient digit is 4, in the tens place.
