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ozzi
4 years ago
10

I need help with this

Mathematics
2 answers:
jasenka [17]4 years ago
8 0

Trey = .4

Luis = .7

Ethan = .5

Roderick = .6

Hope this helps!

Schach [20]4 years ago
6 0
The answer is B Luis because he only read 1.4 pages a minute.
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PLEASEE HELP!!
Alex777 [14]

Answer:

<h2>A)t=6.7</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic equation
  • quadratic equation word problems
  • solving quadratic
<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

t

<h3>tips and formulas:</h3>
  • <u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
  • <u>solving</u><u> </u><u>quadratics </u><u>using</u><u> </u><u>quadratic</u><u> formula</u>
  • <u>PEMDAS</u>
<h3>let's solve: </h3>

step - 1 :  \: define

- 4 {t}^{2}  + 12t + 100 = 0

step - 2 :  \\ divide \: both \: sides \: by \:  - 4

{t}^{2}  - 3t - 25 = 0

step - 3 :  \\ solve \: the \: quadratic

formula :  \\ x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac }  }{2a}

define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \:  - 25 \: respectively

t =  \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 }  }{2.1}

t =  \frac{  3± \sqrt{ 9    + 100}  }{2}

t = \frac{3 +  \sqrt{ 109 } }{2}

t =  \frac{3  -  \sqrt{ 109 } }{2}

t = 6.7 \\ t =  - 3.7

as \: we \: know \: time \: cannot \: be \: negative

\huge \therefore \: t = 6.7

5 0
3 years ago
I need help with this please​
finlep [7]

like i said the ? would be a 5

5 0
3 years ago
Wich expression shows the product of 9 and a number?
Monica [59]

Answer:

There are two and they both mean the same thing.

Step-by-step explanation:

1. 9 x (times) n

2. 9n

I hope this helps u! :D

5 0
3 years ago
I am confused and i dont know how i would do this
Crank

Answer:

5760

Step-by-step explanation:

I do 12 x 12 x 10 x 4= 5760

3 0
3 years ago
Write a problem that can be solved with a bar model that shows equal groups of liters
ioda
"In Grade 2 and early in Grade 3, students learned to use bar models to solve two-step problems involving addition and subtraction. This is extended in this chapter to include multiplication and division.


<span>Both multiplication and division are based on the concept of equal groups, or the part-part-whole concept, where each equal group is one part of the whole. In Grade 2, students showed this with one long bar (the whole) divided up into equal-sized parts, or units. This unitary bar model represents situations such as basket of apples being grouped equally into bags." </span>https://www.sophia.org/tutorials/math-in-focus-chapter-9-bar-modeling-with-multipli
8 0
3 years ago
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